36y^2+0-49=0

Solution for 36y^2+0-49=0 equation:

36y^2+0-49=0

We add all the numbers together, and all the variables

36y^2-49=0

a = 36; b = 0; c = -49;
Δ = b2-4ac
Δ = 02-4·36·(-49)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-84}{2*36}=\frac{-84}{72}
=-1+1/6
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+84}{2*36}=\frac{84}{72}
=1+1/6
$